Q = 100 J = m cp * (tf ti), where cp=specific of Hg
increase in temp = (tf ti) = 100 J / [2 g*0.1395(J/g-c)]
increase in temp = (tf ti) = 100 J / [2 g*0.1395(J/g-c)]
Q = 100 J = m cp * (tf ti), where cp=specific of Hg
delta (t) = 358.42 deg C
It is so high because of very low specific heat of Hg (mercury)
for water, cp = 4.1813 J/g-C
Q (H2o-needed) = 20 * 4.1813* (358.42)
= 29973.23 Joules
= about 300 times more heat is need by the water
This post is last updated on hrtanswers.com at Date : 1st of September – 2022