Ive tried the
I bought 3951.75 years. Is that appropriate
0.62 = 0.5^(t/5730)
log0.62 = (t/5730)log0.5
=> t = (log0.62/log0.5) x 5730 ~ 3951.75
This post is last updated on hrtanswers.com at Date : 1st of September – 2022
Ive tried the
I bought 3951.75 years. Is that appropriate
0.62 = 0.5^(t/5730)
log0.62 = (t/5730)log0.5
=> t = (log0.62/log0.5) x 5730 ~ 3951.75
This post is last updated on hrtanswers.com at Date : 1st of September – 2022