A jet moving at 500.0 km/h due east moves into a region where the wind is blowing at 120.0 km/h in. [Solved]

Return to polar form

Magnitude = sqrt(603.923^2 60^2) = 606.9
Direction = arctan(60 / 603.923) = 5.67 degrees north of east

Decompose each vector into x-y

500 km/h due east = (500, 0)
120 km/h at 30 deg. north of east
= (120 cos(30), 120 * sin(30))
= (120 * sqrt(3) / 2, 120 * 1 / 2)
= (60 * sqrt(3), 60)

Add the vectors.
(500, 0) (60 * sqrt(3), 60)
= (500 60 * sqrt(3), 60)
= (603.923, 60)

Magnitude = sqrt(603.923^2 60^2) = 606.9
Direction = arctan(60 / 603.923) = 5.67 degrees north of east

Magnitude = sqrt(603.923^2 60^2) = 606.9
Direction = arctan(60 / 603.923) = 5.67 degrees north of east

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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