A metal foil has a threshold frequency of 5.45 x 10^14 Hz. [Solved]

lambda = c / nu = (3.00 x 10^8 m/s) / (5.45 x 10^14 s^-1) = 5.50 x 10^-7 m = 550 nm = green light
Any color of light with a wavelength less than 550 nm would do the job (green, blue, indigo, violet)

c(speed of light)=wavelength/frequency
ergo:
if f(color)>5.4510^14hz
electrons will be ejected.

lambda = c / nu = (3.00 x 10^8 m/s) / (5.45 x 10^14 s^-1) = 5.50 x 10^-7 m = 550 nm = green light
Any color of light with a wavelength less than 550 nm would do the job (green, blue, indigo, violet)

lambda = c / nu = (3.00 x 10^8 m/s) / (5.45 x 10^14 s^-1) = 5.50 x 10^-7 m = 550 nm = green light
Any color of light with a wavelength less than 550 nm would do the job (green, blue, indigo, violet)

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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