A mixture containing 9 mol of F2 and 4 mol of S is allowed to react. [Solved]

With 3 mol S reacted, 9 mol of F2 will have reacted, so there will be 0 mol F2 remaining, and F2 will be the limiting reactant.

The ratio of moles of S to moles of F2 is 1:3.
Three moles of S require all nine moles of F2. No F2 remains unreacted.
One mole of S remains unreacted, however.

With 3 mol S reacted, 9 mol of F2 will have reacted, so there will be 0 mol F2 remaining, and F2 will be the limiting reactant.

This post is last updated on hrtanswers.com at Date : 1st of September – 2022