# A pebble is dropped down a well and hits water 1.5 seconds later. Using the equations for motion with constan [Solved] y=y0 v0t-gt^2/2

How to solve these kinematics problems:
1) Identify what you know
time = 1.5s
acceleration due to gravity = 9.8m/s^2
initial height = x0 = 0m
initial velocity = v0 = 0m/s

2) Identify what you dont know
height (x)

y=0 0-9.81*1.5^2/2=-11.04 m (or positive if you flip your axis)

4) Plug in what you know and solve:
x = 0 0*t (1/2) * (-9.8) * (1.5)^2
x = -11.025 m

4) Plug in what you know and solve:
x = 0 0*t (1/2) * (-9.8) * (1.5)^2
x = -11.025 m

4) Plug in what you know and solve:
x = 0 0*t (1/2) * (-9.8) * (1.5)^2
x = -11.025 m

Dont ask twice nextime but wait for ppl.(an space the time btw which u ask a question)
V=u gt note g can be 10 or 9.8 but I used 10 since it is the general one.
V=0 10*1.5 = V=15 0=15m/s
V^2=u^2 2gh
15^2-=0^2 2*10*S
225=20s
S=225/20=11.25m=11.3m

Dont ask twice nextime but wait for ppl.(an space the time btw which u ask a question)
V=u gt note g can be 10 or 9.8 but I used 10 since it is the general one.
V=0 10*1.5 = V=15 0=15m/s
V^2=u^2 2gh
15^2-=0^2 2*10*S
225=20s
S=225/20=11.25m=11.3m

y=0 0-9.81*1.5^2/2=-11.04 m (or positive if you flip your axis)

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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