# A sample of CH2F2 with a mass of 19 g contains __________ atoms of F. [Solved]

thank you soo much, ive been stuck on this question a while now lol

There are two significant figures:
4.4 x 10^23 atoms Fluorine

There are two significant figures:
4.4 x 10^23 atoms Fluorine

Source(s): Chemistry Major

Molar mass CH2F2 = 52.0235 g/mol
19g = 19/52.0235 = 0.3652 mol CH2F2
0.3652 mol = 6.022*10^23*0.3652 = 2.2*10^23 molecules
Each molecule has 2 F atoms
Number og F atoms = 2.2*10^23 *2 = 4.4*10^23 F atoms.

There are two moles of Fluorine for every mole of the molecule, so there are 0.730441 moles of Fluorine
2 x 0.36522 = 0.730441

Next, avogadros number lets us know how many atoms are in this many moles of fluorine
6.02 x 10^23 x 0.730441 = 4.39871 x 10^23 atoms

There are two significant figures:
4.4 x 10^23 atoms Fluorine

I got this answer as follows:

Molar mass CH2F2 = 52.0235 g/mol
19g = 19/52.0235 = 0.3652 mol CH2F2
0.3652 mol = 6.022*10^23*0.3652 = 2.2*10^23 molecules
Each molecule has 2 F atoms
Number og F atoms = 2.2*10^23 *2 = 4.4*10^23 F atoms.

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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