# A water tank has the shape of a cone. its 10m high and radius is 3m at the top [Solved] space = pi(1.5)^2 = about 7.068583471 m^2

we could eind the radius of the outside of water. by related triangle- correct of cone/correct of water=radius of cone/radius of water flooring 10/5=3/r r=one million.5 meter flooring portion of correct of water=(22/7)r^2 = (22/7)x1.5^2 = 3.142.25 =7.0.5 m^2

we could eind the radius of the outside of water. by related triangle- correct of cone/correct of water=radius of cone/radius of water flooring 10/5=3/r r=one million.5 meter flooring portion of correct of water=(22/7)r^2 = (22/7)x1.5^2 = 3.142.25 =7.0.5 m^2

10/5 = 6/X
X = 3
So the bottom of the triangle is 3 m, and the radius of the cone at this level is 3/2 m.

A circle (floor of the water) with radius 3/2m has an space of
piR^2
or
pi* 9/4 sq. meters
or approx. 7.068 sq. meters.

A circle (floor of the water) with radius 3/2m has an space of
piR^2
or
pi* 9/4 sq. meters
or approx. 7.068 sq. meters.

we could eind the radius of the outside of water. by related triangle- correct of cone/correct of water=radius of cone/radius of water flooring 10/5=3/r r=one million.5 meter flooring portion of correct of water=(22/7)r^2 = (22/7)x1.5^2 = 3.142.25 =7.0.5 m^2