An 80.0-gram sample of a gas was heated from 25 C to 225 C. During this process, 346 J of work was done.. [Solved]

7211 J = 80.0 g x c x (225-25) C

First you need to calculate q
delta U is change in internal energy

delta U = q w
q is heat and w work done
here work was done by the system means energy leaving the system so w is negative

q = m x c x delta T

c = 0.451 J /g C

delta U = q w

delta U = q w
q is heat and w work done
here work was done by the system means energy leaving the system so w is negative

c = 0.451 J /g C

This post is last updated on hrtanswers.com at Date : 1st of September – 2022