Os on right are now 3 (1.52)=6 !!!!
Cs still OK!!!!!!!
4KO2(s) 2CO2(g)->2K2CO3(s0 3O2(g)
4 KO2 2 CO2 >2 K2CO3 6 O2
Cs still OK!!!!!!!
4 KO2 2 CO2 >2 K2CO3 6 O2
2KO2(s) CO2(g) > K2CO3(s) O2(g)
It is a useful tool to balance an equation but if you are not allowed to use it just double everything
6[can you see why (22) 2] Os on left
.
TO GET 6 Os ON RIGHT PUT 1.5O2
Cs still OK!!!!!!!
It is a useful tool to balance an equation but if you are not allowed to use it just double everything
SOME TUTORS AND EXAM BOARDS FROWN UPON THE USE OF SIMPLE (0.5) FRACTIONAL
MOLES BEING USED TO BALANCE EQUATIONS, ALTHOUGH AT HIGHER LEVELS OF CHEMISTRY IT IS ACCEPTABLE AND IS USED
Cs still OK!!!!!!!
Os on right are now 3 (1.52)=6 !!!!
4KO2(s) 2CO2(g)->2K2CO3(s0 3O2(g)
4 KO2 2 CO2 >2 K2CO3 6 O2
Look for some atom which is easy to balance eg K
4KO2(s) 2CO2(g) > 2K2CO3(s) 3O2(g)
This post is last updated on hrtanswers.com at Date : 1st of September – 2022