i cant view the link to the image, but

also you have to consider resistors in series and parallel, maybe even use kerchoffs laws.

Post your question here and upload the image, ill help u

http://www.edu.faq.cm/domyhw

d)Calculate the current in 110

resistor 61/110 =0.554

Vx R Vx R Vx R = -58 R 3V R GND R

Vx 202 Vx 135 Vx 64 = -58 202 3V 135 0V 64

Vx( ) = –

Vx -9.46673V

the current formula is V = IR,

(a) (Vx 3V) R = (-9.46673V 3V) 135 -92.346mA

(b) (Vx -58V) R = (-9.46673V -58V) 202 240.264mA

(c) (Vx GND) R = (-9.46673V 0V) 64 -147.918mA

(d) same as (a), so: -92.346mA

(e) same as (b), so: 240.264mA

also you have to consider resistors in series and parallel, maybe even use kerchoffs laws.

Lets start the fun!

Not sure bout calculations but sure about the rules!

d)Calculate the current in 110

resistor 61/110 =0.554

a) Calculate the current in 25

resistor (series) 61/25 0 = 2.44 Ampere

b)Calculate the current in 120

resistor 61/120 =0.5A

c)Calculate the current in 64

resistor 61/64= 0.95A

d)Calculate the current in 110

resistor 61/110 =0.554

e)Calculate the current in 82

resistor (series) 61/82= 0.744a

Not sure bout calculations but sure about the rules!

So, now you can answer the questions. The current in R will be the same as the current in the 120 and the 82 resistors. The current in R will be the same as the current in the 25 and 110 resistors. The current in R is the current in the 64 resistor.

a) Calculate the current in 25

resistor (series) 61/25 0 = 2.44 Ampere

Lets start the fun!

Post your question here and upload the image, ill help u

http://www.edu.faq.cm/domyhw

This post is last updated on hrtanswers.com at Date : 1st of September – 2022