# Calculate the fraction of HNO2 that has dissociated. [Solved] Moles HNO2 = 5.000 g / 47.013 g/mol = 0.1063 moles HNO2
As a result of this was dissolved in 1 kg water, the molality of undissociated HNO2 is 0.1063 molal
Molality of solute:
Change in Freezing level = Kf m
0.2100 = 1.853 C/m (m)
m = 0.1133 molal
Now, the distinction between the molality calculated from the mass and that calculated from the freezing level despair signifies the moles of HNO2 that dissociated.
Fraction dissociated = (0.1133 -0.1063) / 0.1063 = 0.06613 or 6.613% dissociated
(NOTE: Usually the Kf for water is reported as 1.86 C/m. I discovered this worth to 4 vital figures on-line. If youre given solely the traditional worth for Kf, I might use that in the issue, although that introduces an error.)

Moles HNO2 = 5.000 g / 47.013 g/mol = 0.1063 moles HNO2
As a result of this was dissolved in 1 kg water, the molality of undissociated HNO2 is 0.1063 molal
Molality of solute:
Change in Freezing level = Kf m
0.2100 = 1.853 C/m (m)
m = 0.1133 molal
Now, the distinction between the molality calculated from the mass and that calculated from the freezing level despair signifies the moles of HNO2 that dissociated.
Fraction dissociated = (0.1133 -0.1063) / 0.1063 = 0.06613 or 6.613% dissociated
(NOTE: Usually the Kf for water is reported as 1.86 C/m. I discovered this worth to 4 vital figures on-line. If youre given solely the traditional worth for Kf, I might use that in the issue, although that introduces an error.)

AHHHHH SO HARD

This post is last updated on hrtanswers.com at Date : 1st of September – 2022