Let v be the magnitude of velocity of grasshopper

Let v be the magnitude of velocity of grasshopper

(v sin50)^2 = 29.80.0674 or v^2 = 1.32104/ sin^2 50 = 2.2512 or

v =1.5 m/s

Time of flight 1.06/ (v cos 50) = (1.06/1.5)/cos 50 = 1.099s

Time to reach maximum height = (1.5 sin 50)/9.8 =0.1175 s

The time taken for grasshopper to come down from the topmost position = 0.9815 s

The total height travelled from topmost position

0.59.80.9815 = 4.809

Height of cliff = 4.8093 0.0674 = 4.742 m

The people who answer this stuff are idiots for not giving the original formula or where they got numbers from.

This post is last updated on hrtanswers.com at Date : 1st of September – 2022