Let v be the magnitude of velocity of grasshopper
Let v be the magnitude of velocity of grasshopper
(v sin50)^2 = 29.80.0674 or v^2 = 1.32104/ sin^2 50 = 2.2512 or
v =1.5 m/s
Time of flight 1.06/ (v cos 50) = (1.06/1.5)/cos 50 = 1.099s
Time to reach maximum height = (1.5 sin 50)/9.8 =0.1175 s
The time taken for grasshopper to come down from the topmost position = 0.9815 s
The total height travelled from topmost position
0.59.80.9815 = 4.809
Height of cliff = 4.8093 0.0674 = 4.742 m
The people who answer this stuff are idiots for not giving the original formula or where they got numbers from.
This post is last updated on hrtanswers.com at Date : 1st of September – 2022