# Consider the circuit shown in (Figure 1). Assume I = 0.94 A. What is the value of resistor R [Solved]

or a neater means

You understand the voltage throughout the left 10 = 10*0.94A = 9.4V
Thus thats the voltage throughout the 15 and R.
Subsequently the present within the 15 = 9.4/15 = 94/150 = 47/75 A
Kirchoffs present legislation says present in = present out and there 2A coming into and 0.94 47/75 = 141/150 94/150 = 235/150 = 47/30 leaving. Thus 2A = 60/30 and (60-47)/30=13/30 A should go proper and down into R. We all know the voltage throughout R = 9.4V = the voltage throughout the 15 and = that throughout the 10.
Now we will write: 9.4V = 13/30 A *R. Subsequently R = 9.4/(13/30) = 282/13
282/13 = 21.7 = R or 22 with 2 vital digits.

E=I*R = .94*10=9.4v.
I=E/R = 9.4/15 = .627A
R= E/I = 9.4/(2-(.627 .94) = 9.4/.433 = 21.7.
R=21.7
Excellent drawback.

Since you already know the present by means of the ten and 15 ohm resistors, you possibly can calculate the present by means of R and determine its worth.

or a neater means

Since you already know the present by means of the ten and 15 ohm resistors, you possibly can calculate the present by means of R and determine its worth.

Now that you already know the voltage throughout all three resistors, you possibly can calculate the mixed resistance off all three resistors in parallel and clear up for R. (trace: R = E / I)

This post is last updated on hrtanswers.com at Date : 1st of September – 2022