Ill let you do K just to save space. Basically, you do the same calculations as Na. Remember that we do not count the valence electron in the fourth shell. There are 8 electrons in the third shell, so multiply these by 0.85. There are 10 electrons remaining in the first and second shells, so multiply these by 1.00. Subtract from the Z value, 19, and you should get 2.20 for the Zeff value, just as we did with Na.

Finding the Z value for Na is easy: just look at its atomic number. Since Na is #11, this means its Z value is 11.

Ill let you do K just to save space. Basically, you do the same calculations as Na. Remember that we do not count the valence electron in the fourth shell. There are 8 electrons in the third shell, so multiply these by 0.85. There are 10 electrons remaining in the first and second shells, so multiply these by 1.00. Subtract from the Z value, 19, and you should get 2.20 for the Zeff value, just as we did with Na.

For the S value, look at the electron configuration for Na: (1s^2)(2s^2)(2p^6)(3s^1)

Valence electrons are the electrons in its outermost shell. For Na, this is the electron in the third shell. Since valence electrons contribute 0 to the S value, we do not count this electron when calculating.

There are 8 electrons in the second shell of Na. These electrons have a value of 2 since they are in the second shell. Since 2 is one less than 3, these electrons contribute 0.85 to the S value. Multiply 0.85 by the 8 electrons in the second shell and you get 6.80.

Now just plug these values in the equation up above: 11-10= 1

So the Zeff charge of Na is 1.

Finding the Z value for Na is easy: just look at its atomic number. Since Na is #11, this means its Z value is 11.

Since Na is in the third row of the periodic table, n=3. We cant count the valence electron in the third shell since this is the outermost electron that we are trying to find the value of.

Source(s): Im a Chem major, and were currently learning this stuff.

There are 2 electrons remaining in the first shell. These will contribute 1.00 to the S value. Multiply 1.00 by the 2 electrons and you get 2.00.

Now add these two values to get S: 6.80 2.00= 8.80.

The Z value for Na is still the same: 11.

Just plug in to the equation we started with, and you get 11-8.80=2.20. Thus, according to Slaters rules, the Zeff of Na is estimated to be 2.20.

1) Electrons with the same value as the n value of the element contribute 0.35 to the S value.

2) Electrons with the value of one less than the n value contribute 0.85 to the S value.

3) All other electrons remaining contribute 1.00 to the S value.

There are 2 electrons remaining in the first shell. These will contribute 1.00 to the S value. Multiply 1.00 by the 2 electrons and you get 2.00.

So using these rules, lets look at Zeff for Na:

Just plug in to the equation we started with, and you get 11-8.80=2.20. Thus, according to Slaters rules, the Zeff of Na is estimated to be 2.20.

Now add these two values to get S: 6.80 2.00= 8.80.

The Z value for Na is still the same: 11.

Now add these two values to get S: 6.80 2.00= 8.80.

The Z value for Na is still the same: 11.

Source(s): Im a Chem major, and were currently learning this stuff.

K is #19 on the periodic table, so Z=19.

For K, the method is similar. The electron configuration of K is:(1s^2)(2s^2)(2p^6)(3s^2)(3p^6)(4s^1)

This post is last updated on hrtanswers.com at Date : 1st of September – 2022