Calculate [OH-]:
pH = 8.12
Supply(s): ChemTeam
Wed like the Ka of HF:
Supply(s): ChemTeam
Supply(s): ChemTeam
The reply on Mastering Chemistry was 1.8*10^-6=OH-
Maybe there was some rounding off that you just did otherwise or maybe the one who ready the reply used a special Kb than you probably did (or was supplied in the issue).
The reply on Mastering Chemistry was 1.8*10^-6=OH-
Calculate [OH-]:
The reply on Mastering Chemistry was 1.8*10^-6=OH-
Supply(s): ChemTeam
pH = 8.12
Maybe there was some rounding off that you just did otherwise or maybe the one who ready the reply used a special Kb than you probably did (or was supplied in the issue).
Kb = 1.5873 x 10^-11 (I will not hassle to spherical off but)
The proper reply is 1.7*10^-6M. First, write equilibrium F- H20 <=> HF H30 whole an ICE desk. Ka = 3.5*10^-4. However, have to make use of Kb price. To hunt out Kb use the connection Ka*Kb=Kw, the place Kw = 1.Zero*10^-14. Kb= 2.Eighty 5*10^-11. 2.Eighty 5*10^-11= x^2 / 0.10-x. Assume x is smaller than zero.100 (aka small x approximation). The OH- equals 1.Sixty eight*10^-6.
6.3 x 10^-4
This post is last updated on hrtanswers.com at Date : 1st of September – 2022