Find the dimensions of a rectangle with perimeter 108 m whose area is as large as possible [Solved]

Answer:
27 m by 27 m

Answer:
27 m by 27 m

The dimensions of a rectangle with perimeter 108 m
whose area is as large as possible

For the rectangle to have the maximum area, the dimensions should be equal.
Let the dimensions be x
thus the perimeter will be:
2(x x) = 108
2(2x) = 108
4x = 108
x = 27
thus for the rectangle to have a maximum area the dimensions should be 27m by 27 m

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That would be a square 4 equal sides.
108/4 = 27 m

Answer:
27 m by 27 m

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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