Answer:

27 m by 27 m

Answer:

27 m by 27 m

The dimensions of a rectangle with perimeter 108 m

whose area is as large as possible

For the rectangle to have the maximum area, the dimensions should be equal.

Let the dimensions be x

thus the perimeter will be:

2(x x) = 108

2(2x) = 108

4x = 108

x = 27

thus for the rectangle to have a maximum area the dimensions should be 27m by 27 m

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That would be a square 4 equal sides.

108/4 = 27 m

Answer:

27 m by 27 m

This post is last updated on hrtanswers.com at Date : 1st of September – 2022