Find the volume of 0.130 M hydrochloric acid necessary to react completely with 1.55g Al(OH)3. [Solved]

Can somebody assist with this downside, Ive tried all types of equations to determine this out, however cant get the precise reply. Thanks!

begin with balanced equation:
3 HCl Al(OH)3 > AlCl3 3 H2O

0.0600 moles HCl / 0.130 moles/L = 0.46 L = 460 mL

0.0600 moles HCl / 0.130 moles/L = 0.46 L = 460 mL

you want 3 x 0.0200 moles HCl in keeping with the method.

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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