How many grams of aluminum can form by passing 386 C through an electrolytic cell containing a molten aluminum salt [Solved]

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Al 3 3e- == Al(s)

Al 3 3e- == Al(s)

0.00133 moles Al x 27.0 grams Al / 1mole Al = 0.0359 grams Al

0.00133 moles Al x 27.0 grams Al / 1mole Al = 0.0359 grams Al

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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