How many moles of O2 are produced when 0.325mol of KO2 reacts in this fashion [Solved]

My research query says that:The response between potassium superoxide, KO2, and CO2,

4 KO2 2 CO2 2 K2CO3 3 O2
(0.325 mol KO2) x (3 mol O2 / 4 mol KO2) = 0.244 mol O2
(8.5 g O2) / (31.99886 g O2/mol) x (4 mol KO2 / 3 mol O2) x ( g KO2/mol) = 71 g KO2
(8.5 g O2) / (31.99886 g O2/mol) x (2 mol CO2 / 3 mol O2) x (44.00964 g CO2/mol) =
7.8 g CO2

4 KO2 2 CO2 2 K2CO3 3 O2
(0.325 mol KO2) x (3 mol O2 / 4 mol KO2) = 0.244 mol O2
(8.5 g O2) / (31.99886 g O2/mol) x (4 mol KO2 / 3 mol O2) x ( g KO2/mol) = 71 g KO2
(8.5 g O2) / (31.99886 g O2/mol) x (2 mol CO2 / 3 mol O2) x (44.00964 g CO2/mol) =
7.8 g CO2

This post is last updated on hrtanswers.com at Date : 1st of September – 2022