There are five, so there are FIVE pi bonds present my young chemist!
5 , 3 for the benzene ring , 1 for the acetyl group, 1 for the acid
We draw the Lewis structure (you can see it here):
http://en.wikipedia.org/wiki/Acetylsalicylic_acid
5 , 3 for the benzene ring , 1 for the acetyl group, 1 for the acid
There are five, so there are FIVE pi bonds present my young chemist!
and every single bond is a sigma, a double bond is a sigma and a pi and a triple is a sigma and two pi.
CH3COOH has 7 sigma bonds, they are all the C-H bonds (3 total), C-C bond (1 total), C-O bond (1 total), O-H bond (1 total) and one from the C=O. It has 1 pi bond which is the C=O bond. So the answer is E. I hope this helps.
You just want pi bonds and there are no triple bonds, so just count the double bonds.
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