A slingshot will shoot a 10-g pebble 22.0m straight up. (A) how much potential energy is stored in the slingshots rubber band (B) with the same potential energy stored in the rubber band, how high can the slingshot shoot a 25-g pebble (C) what physical effects did you ignore in solving this problem
a) p.e stored in sling = potential energy gained by pebble (Conservation of Energy)
= mgh = (10/1000)kg x 9.81 m/s x 22 m = 2.1582 Joules
b) for a 25 g pebble
=> 2.1582 = (25/1000) 9.81(h)
h = [40 x 2.1582] / 9.81
h = 8.8 m
c) loss of energy as heat due to frictional dissipation of energy via air resistance (ignoring air resistance and related friction)
also assuming the sling is stretched and released identically in both situations so that the same p.e is stored/imparted to the pebbles.
hope this helps
gravitational potential energy = kinetic energy = elastic potential energy
mgh = (1/2)mv^2
m = mass in kg
g= 9.8m/s^2
h = height in metres
usually air resistance is ignored
sound energy from the rubber band is also probably ignored too
This post is last updated on hrtanswers.com at Date : 1st of September – 2022