A solution was prepared by dissolving 29.0 g of KCl in 225 g of water.
b) 225 g water
mol = 225g / 18.016g/mol = 12.5 mol water
29.0 g KCl
mol = 29.0 / 74.55g/mol = 0.389 mol KCl
Therefore mole fraction KCl = 0.389 / (.389 12.5) = 0.030
Molarity = 0.389mol / 0.239L = 1.63 mol/L
c) from above, mol KCl is 0.389, vol = 0.239L
Mass percent and mole fraction work pretty much the same way they are both percentages. Any percent is sample / total x 100.
A) is straight forward. B) Convert both to moles and the sample / total.
C) If the solvent is water, then molarity and molality are the same thing as the density of water 1g/ml Liters = Kilograms.
Convert the KCl to mole and then divide by lters.
I can only answer A. Divide KCl with H20. So 29g/225g = 0.13 times 100. Its about 13% mass in the solution.
This post is last updated on hrtanswers.com at Date : 1st of September – 2022