Reply 2
To calculate this well use someformulation of theHardy-Weinberg principle:p 2pq q = 1andp q = 1where: p the frequency ofthe A allele.q the frequency ofthe a allele. p the frequency of dominant homozygote (with AA genotype) 2pq the frequency of heterozygote (with Aa genotype) qthe frequency of recessive homozygote (with aa genotype) Everyone knows: p = 70% = 70/100 = 0.7 q = 30% = 30/100 = 0.3 Weve to calculate the frequency of the genotype aa: q = Since everyone knows the frequency of allele q, it is easy to calculate the frequency of the genotype aa: q = 0.3 = 0.09 = 0.09 100% = 9%
Reply 3
To calculate this well use someformulation of theHardy-Weinberg principle:p 2pq q = 1andp q = 1where: p the frequency ofthe A allele.q the frequency ofthe a allele. p the frequency of dominant homozygote (with AA genotype) 2pq the frequency of heterozygote (with Aa genotype) qthe frequency of recessive homozygote (with aa genotype) Everyone knows: p = 70% = 70/100 = 0.7 q = 30% = 30/100 = 0.3 Weve to calculate the frequency of the genotype aa: q = Since everyone knows the frequency of allele q, it is easy to calculate the frequency of the genotype aa: q = 0.3 = 0.09 = 0.09 100% = 9%
To calculate this well use someformulation of theHardy-Weinberg principle:p 2pq q = 1andp q = 1where: p the frequency ofthe A allele.q the frequency ofthe a allele. p the frequency of dominant homozygote (with AA genotype) 2pq the frequency of heterozygote (with Aa genotype) qthe frequency of recessive homozygote (with aa genotype) Everyone knows: p = 70% = 70/100 = 0.7 q = 30% = 30/100 = 0.3 Weve to calculate the frequency of the genotype aa: q = Since everyone knows the frequency of allele q, it is easy to calculate the frequency of the genotype aa: q = 0.3 = 0.09 = 0.09 100% = 9%
Reply 2
Reply 3
This post is last updated on hrtanswers.com at Date : 1st of September – 2022