# Kara is building a sandbox shaped like a kite for her nephew. the top two sides of the sandbox are 29 inches long. the bottom two [Solved] Kara is constructing a sandbox formed like a kite for her nephew. the highest two sides of the sandbox are 29 inches lengthy. the underside two sides are 25 inches lengthy. the diagonal db has a size of 40 inches. whats the size of the diagonal ac inches

The reply is 36 i took the take a look at

Case 1: Diagonalis fashioned by connecting the vertices fashioned by the assembly factors of a 25-inch facet and a 29-inch facet.Name the intersection level of and E. bisects , so. Because the diagonals of a kite are perpendicular to one another, and are each proper triangles. One has a hypotenuse of , and the opposite has a hypotenuse of , however each share a leg of . Utilizing the Pythagorean Theorem, we will get that the size of the opposite leg within the triangle with a hypotenuse of is . Equally, for the triangle with a hypotenuse of , the opposite leg has a size of . Collectively, these legs make up , which means , our last reply. Case 2: Diagonalis fashioned by connecting the vertices fashioned by the assembly factors of the edges with equal lengths.Name the intersection level of and E. We are going to give attention to two triangles, particularly and . Since diagonals intersect perpendicularly, these triangles are proper triangles. Certainly one of them has a hypotenuse of , and the opposite has a hypotenuse of . They each share a leg thats half of as a result of bisects . Let and the non-shared leg of the proper triangle with a hypotenuse of equal . Since , the non-shared leg of the opposite proper triangle (the one with a hypotenuse of ) has a size of . Utilizing the Pythagorean Theorem, we will get the equations and. These can simplify to and. Isolating the time period , we will get and. The latter can simplify to. Utilizing substitution, we will mix the 2 equations into one and get. We are able to simplify that to, which means. Nonetheless, were in search of ( is simply half of ). We are able to resolve for utilizing the Pythagorean Theorem and the triangle with a hypotenuse of and a leg of . We get, which means, our last reply.