1. In NH3, since H is 1, then N have to be -3. Word that N has an oxidation variety of 0 (an uncombined aspect) on the left aspect of the equation. So N went from 0 to -3 by gaining electrons; that is discount. Since N2 was lowered, it brought on the oxidation of H2 and so N2 is the oxidizing agent.
Nitrogen has a -3 cost (i.e. N^3-) when it varieties an ionic bond with a metallic, like AlN. However when N combines with a nonmetal like H, O, and so on., to kind a covalent bond, its oxidation quantity varies. Oxygen normally has a -2 cost; the exception is when its current as peroxide (O2^-) the place every O atom has a -1 cost. H is often 1 until its a part of a metallic hydride (like LiH) the place it has a -1 cost.
1. In NH3, since H is 1, then N have to be -3. Word that N has an oxidation variety of 0 (an uncombined aspect) on the left aspect of the equation. So N went from 0 to -3 by gaining electrons; that is discount. Since N2 was lowered, it brought on the oxidation of H2 and so N2 is the oxidizing agent.
2. O goes from 0 to -2; that is discount. O2 is the oxidizing agent.
N goes from 0 to 1; that is oxidation. N2 is the lowering agent.
2. O goes from 0 to -2; that is discount. O2 is the oxidizing agent.
N goes from 0 to 1; that is oxidation. N2 is the lowering agent.
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