The other two problems work in exactly the same way

and call the 2nd legs routes 1, 2, 3, 4, and 5 you have

For a small set you can list all the choices. If you call the first legs in problem C

So route A combined with her 6 choices for the remainer of the trip is 6 routes for a complete trip.

If she had picked a different route from the school to the library, call it route B. Shes still

got 6 choices of how to complete the trip. So route B combined with her 6 choices is another

6 ways to make a complete trip.

Each of her 5 choices for the first leg of the trip can be completed using one of the 6 choices for

the 2nd leg of the trip.

For a small set you can list all the choices. If you call the first legs in problem C

For a small set you can list all the choices. If you call the first legs in problem C

and you can see that there are 15 total routes for the complete trip.

Each of her 5 choices for the first leg of the trip can be completed using one of the 6 choices for

the 2nd leg of the trip.

and call the 2nd legs routes 1, 2, 3, 4, and 5 you have

and you can see that there are 15 total routes for the complete trip.

C 3 x 5 = 15

A1 A2 A3 A4 A5

B1 B2 B3 B4 B5

C1 C2 C3 C4 C5

The other two problems work in exactly the same way

This post is last updated on hrtanswers.com at Date : 1st of September – 2022