The other two problems work in exactly the same way
and call the 2nd legs routes 1, 2, 3, 4, and 5 you have
For a small set you can list all the choices. If you call the first legs in problem C
So route A combined with her 6 choices for the remainer of the trip is 6 routes for a complete trip.
If she had picked a different route from the school to the library, call it route B. Shes still
got 6 choices of how to complete the trip. So route B combined with her 6 choices is another
6 ways to make a complete trip.
Each of her 5 choices for the first leg of the trip can be completed using one of the 6 choices for
the 2nd leg of the trip.
For a small set you can list all the choices. If you call the first legs in problem C
For a small set you can list all the choices. If you call the first legs in problem C
and you can see that there are 15 total routes for the complete trip.
Each of her 5 choices for the first leg of the trip can be completed using one of the 6 choices for
the 2nd leg of the trip.
and call the 2nd legs routes 1, 2, 3, 4, and 5 you have
and you can see that there are 15 total routes for the complete trip.
C 3 x 5 = 15
A1 A2 A3 A4 A5
B1 B2 B3 B4 B5
C1 C2 C3 C4 C5
The other two problems work in exactly the same way
This post is last updated on hrtanswers.com at Date : 1st of September – 2022