How many oxygen atoms are there in 4.00 g of sodium dichromate, Na2Cr2O7
grams to moles
4.00 g Na2Cr2O7 *1 mol Na2Cr2O7 / 262 g Na2Cr2O7 = 0.0153 mol Na2Cr2O7
moles sodium dichromate to moles oxygen
0.0153 mol Na2Cr2O7 * 7 mol oxygen / 1 mol Na2Cr2O7 = 0.107
mol O
moles oxygen to oxygen atoms
0.107 mol O * 6.02210^23 atoms/mol = 6.4410^22 atoms O
This post is last updated on hrtanswers.com at Date : 1st of September – 2022