(a) If each elastic band stretches 0.280 m while supporting a 5.95-kg child, what is the force constant for each elastic band

(a) Assuming equilibrium,

2 * F = m*g = 5.95kg * 9.8m/s = 58.3 N

F = 29.2 N = kx = k * 0.280m

k = 104 N/m

Hope this helps!

(c) max V = A* = A*2/T

max V = 0.280m * 2 / 1.50s = 1.17 m/s

(b) T = 2(m/k) = 2(5.95kg / 104N/m) = 1.50 s

This post is last updated on hrtanswers.com at Date : 1st of September – 2022