# the equation of the horizontal asymptote for the graph of y =( 2-e^1/x) / ( 2 e^ 1/x) [Solved] y= [ 2 e^(a million/x) ] / [ 2 e^(a million/x) ] Horizontal asymptotes provide us an idea with regard to the highest behaviour of a operate. lim x->infinity [ 2 e^(a million/x) ] / [ 2 e^(a million/x) ] = [ 2 e^(0) ] / [ 2 e^(0) ] = [ 2 a million ] / [ 2 a million ] = 1,000,000 / 3 consequently horizontal asymptote is y=1,000,000/3

If this operate has a horizontal asymptote, its y-value should be
lim[x->infinity]((2 e^(1/x)) / (2 e^(1/x)))

y= [ 2 e^(a million/x) ] / [ 2 e^(a million/x) ] Horizontal asymptotes provide us an idea with regard to the highest behaviour of a operate. lim x->infinity [ 2 e^(a million/x) ] / [ 2 e^(a million/x) ] = [ 2 e^(0) ] / [ 2 e^(0) ] = [ 2 a million ] / [ 2 a million ] = 1,000,000 / 3 consequently horizontal asymptote is y=1,000,000/3

Since lim[x->infinity](e^(1/x)) = 1, the standard elementary theorems on limits guarantee us that the above restrict is (2 1) / (2 1) = 1/3, so the equation of the asymptote is y = 1/3.

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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