# The pH Scale Help!!! [Solved]

pH = -log[H ]
pH = -log(610^-12)
pH = 11.2

a. [H3O ] = 610 M ==> pH = 11.2
b. pH = 4.240 ==>10 ^-4.24 = 5.75 x 10 M
c. [H3O^ ]=10^-2 (pH=2), pH=2.5, pH=4, [H3O^ ]=10^-5 (pH=5) , pH=9

When given the concentration (6 x 10), enter the value then press [log], and the the sign
change key [ /-]. this will be the pH.

a. [H3O ] = 610 M ==> pH = 11.2
b. pH = 4.240 ==>10 ^-4.24 = 5.75 x 10 M
c. [H3O^ ]=10^-2 (pH=2), pH=2.5, pH=4, [H3O^ ]=10^-5 (pH=5) , pH=9

Most acidic Least acidic
[H3O^ ]=10^-2 ..pH=2.5.. pH=4 ..[H3O^ ]=10^-5.. pH=9

B) 10^-4.240 = 5.7510^-5 M

C) most acidic [H3O^ ]=10^-2 > pH=2.5 > pH=4 > [H3O^ ]=10^-5 > pH=9 least acidic

pH = -log[H ]
pH = -log(610^-12)
pH = 11.2

[H ] = 10^-pH
[H ] = 10^-4.240
[H ] = 5.7510^-5 mol/L

original
pH=4 ..pH=9 ..pH=2.5 ..[H3O^ ]=10^-2.. [H3O^ ]=10^-5

Most acidic Least acidic
[H3O^ ]=10^-2 ..pH=2.5.. pH=4 ..[H3O^ ]=10^-5.. pH=9

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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