The pressure 70.0 meters under water is 788 kPa. [Solved]

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P in atm = (788 kPa)(1 atm / 101.325 kPa)
P in atm = 7.7770 atm (ANSWER)
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1) In order to answer this, you need to know that 1 atm = 101.3 kPa. So: (494 kPa) / (101.3 kPa/atm) 4.88 atm Likewise, you need to know that 1 atm = 760 mmHg. So: (4.88 atm) x (760 mmHg/atm) = 3708 mmHg (If your book really doesnt tell about 1 atm = 101.3 kPa and 1 atm = 760 mmHg, youre working from a lousy book. Those are about as fundamental as it gets.) 2) 1.39 L x (1.00 / 90.0) = 0.0154 L 3) The volume increases by the factor 85.5 / 9.00 = 9.5 Other things being constant, the pressure decreases when the volume increases, so the pressure will decrease by a factor of 9.5. 141 atm / 9.5 = 14.8 atm

1 atm = 760 mmHg
1 atm = 101325 Pa (Pascal) = 101.325 kPa (kiloPascal)

P in atm = (788 kPa)(1 atm / 101.325 kPa)
P in atm = 7.7770 atm (ANSWER)
_____________________________

P in mmHg = (788 kPa)(1 atm / 101.325 kPa)(760 mmHg / 1 atm)
P in mmHg = 5910.4861 mmHg (ANSWER)
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P in atm = (788 kPa)(1 atm / 101.325 kPa)
P in atm = 7.7770 atm (ANSWER)
_____________________________

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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