The sum of two numbers is 17

x y = 17
y = 17 x

x y = 145
y = 145 x

Value of x:
(17 x) = 145 x
289 17x 17x x = 145 x
2x 34x = 144
x 17x = 72
x 17/2x = 72 (- 17/2)
x 17/2x = 288/4 289/4
(x 17/2) = 1/4
x 17/2 = 1/2
x = 18/2 or 9

Value of y:
= 17 9
= 8

So, x could be 8 or 9, which would make 17 x equal to 9 or 8.

Proof (sum of their square is 145):
= 9 8
= 81 64
= 145

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9.

The sum of two numbers (x y) is (=) 17.
In mathematical notation, x y = 17.

The sum of their square is 145. Now x squared = x, similarly y squared = y. Sum of their square (x y) is (=) 145.
In mathematical notation, x y = 145.

Recall that from (iii), x = 17 y

x y = 17 . . . . . (i)
x y = 145 . . . . . (ii)

Recall that from (iii), x = 17 y

yeah 9 is good

-Test-
9^2 8^2 = 145
81 64 = 145
145 = 145 Check!!!!!!!!!!!!!!!!!!!
So the larger number it is 9 with either x or y

ok the equation:

2 (x-9) (x-8) = 0

2 quantity > %. 2 letters. how approximately x and y x y = 17 x^2 y^2 = one hundred forty five equipment of equations. resolve between the equations for the two x or y. good: y = x-17. now subsitute into the different equation: x^2 (x-17)^2 = one hundred forty five x^2 x^2-34x 289=one hundred forty five subtract one hundred forty five from the two factors. integrate x^2 to 2x^2 2x^2 34x one hundred forty four = 0 divide each thing via 2 x^2 17x seventy two = 0 ingredient (x-9)(x-8) = 0 x = 9, x = 8 the two are valid suggestions to the unique question. Coincidentally in case you plug the two in to the equation x y=17 you get y=8 and y=9 (respectively). So the bigger # in all of this could be 9.

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yeah 9 is good

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Source(s): Love Math

Larger # is 9

-Test-
9^2 8^2 = 145
81 64 = 145
145 = 145 Check!!!!!!!!!!!!!!!!!!!
So the larger number it is 9 with either x or y

Larger # is 9

Recall that from (iii), x = 17 y

ok the equation:

yeah 9 is good

(y 9)(y 8) = 0

So, x could be 8 or 9, which would make 17 x equal to 9 or 8.

x^2 y^2 = 145
so substitute.
x = 17 y
(17 y) ^2 y^2 = 145
289 34y y^2 y^2 = 145
-34y 2y^2 = -144
2y^2 34y 144 = 0
(0.5)(y^2 34y 288)
(0.5)(y 16)(y 18) All this here is the AC Method
(0.5)(2y 16)(2y 18)
(2y 16)(y 9)
2y 16 = 0 or y = 9
y = 8 y = 9

Answer 7

To answer algebraically, you should take x and 17 x as your two numbers. Start with
x^2 (17-x)^2 = 145

and solve for x.
2 x^2 34 x 144 =0

2(y 17y 72) = 0

(17 y)(17 y) y = 145

2 quantity > %. 2 letters. how approximately x and y x y = 17 x^2 y^2 = one hundred forty five equipment of equations. resolve between the equations for the two x or y. good: y = x-17. now subsitute into the different equation: x^2 (x-17)^2 = one hundred forty five x^2 x^2-34x 289=one hundred forty five subtract one hundred forty five from the two factors. integrate x^2 to 2x^2 2x^2 34x one hundred forty four = 0 divide each thing via 2 x^2 17x seventy two = 0 ingredient (x-9)(x-8) = 0 x = 9, x = 8 the two are valid suggestions to the unique question. Coincidentally in case you plug the two in to the equation x y=17 you get y=8 and y=9 (respectively). So the bigger # in all of this could be 9.

9.

Answer 6

x^2 y^2 = 145
so substitute.
x = 17 y
(17 y) ^2 y^2 = 145
289 34y y^2 y^2 = 145
-34y 2y^2 = -144
2y^2 34y 144 = 0
(0.5)(y^2 34y 288)
(0.5)(y 16)(y 18) All this here is the AC Method
(0.5)(2y 16)(2y 18)
(2y 16)(y 9)
2y 16 = 0 or y = 9
y = 8 y = 9

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Now.
x 9 = 17
x = 8 or x = 9

So.
x = 9 or 8
y = 8 or 9
so actually x = 9 and y = 8 -or- x = 8 and y = 9

-Test-
9^2 8^2 = 145
81 64 = 145
145 = 145 Check!!!!!!!!!!!!!!!!!!!
So the larger number it is 9 with either x or y

Answer 6

Hope I Helped!

Answer: 9

Source(s): Love Math

9 8=17
9*9=81
8*8=64
64 81=145

9 8=17
9*9=81
8*8=64
64 81=145

2 (x-9) (x-8) = 0

The sum of two numbers (x y) is (=) 17.
In mathematical notation, x y = 17.

So the two numbers are 8 and 9 either way and 9 is the larger.

This post is last updated on hrtanswers.com at Date : 1st of September – 2022