Under certain conditions, the average rate of appearance of oxygen gas in the reaction: 2O3(g)>3O2(g) [Solved]

d(O3)/dt = (2/3)d(O2)/dt = (2/3)(1.210^-3 atm/s) = 8.010^-4 atm/s

d(O3)/dt = (2/3)d(O2)/dt = (2/3)(1.210^-3 atm/s) = 8.010^-4 atm/s

subsequently,

subsequently,

d(O3)/dt = (2/3)d(O2)/dt = (2/3)(1.210^-3 atm/s) = 8.010^-4 atm/s

This post is last updated on hrtanswers.com at Date : 1st of September – 2022