A 45 kg figure skater is rotating on feet of the woman skates at 1.0rev/sec . The woman hands are outstretched in terms of theyll get. Within orientation, the skater could be modeled as a cylindrical torso (40kg, 20cm typical diameter, 160cm high) plus two rod-like hands (2.5 kg each, 66 cm long) connected to the outside the torso. The skater then raises the woman hands directly above the woman mind, in which she is apparently a 45kg , 20-cm-diameter, 200-cm-tall cylinder.
w = 1.306 / 0.225 ==> w = 5.804444 rev/s
[kg * m^2]
We * w (last) = We * w (initial)
[kg * m^2]
We = m * r^2 / 2 ==> We = 0.225 [rev/s].
W/ .6 at first, 3.7 rev/s
Therefore, utilising the equation for angular energy, we understand the lady initial energy is:
and w may be the angular velocity of this item.
In which we may be the minute of inertia of this item
This is actually the minute of inertia for starters supply. We curently have as soon as of inertia on her behalf human body, so we are able to include the human body plus two hands to have the woman total minute of inertia:
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We = m * L^2 / 12 ==> We = 0.09075
And lastly:
We = 0.09075 2.5 * 0.43^2 ==> We = 0.553
w = 1.306 / I
We = 0.2 2 * (0.553) == > We = 1.306
And lastly:
We = m * r^2 / 2 ==> We = 0.2 [kg * m^2]
w = 1.306 / I
We = 0.2 2 * (0.553) == > We = 1.306
w = 1.306 / I
We = 0.2 2 * (0.553) == > We = 1.306
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We = m * L^2 / 12 ==> We = 0.09075
The idea you are working with heres: Conservation of Angular Momentum (just like preservation of energy, however in the rotational globe). Angular Momentum (L) can be located utilizing:
This post is last updated on hrtanswers.com at Date : 1st of September – 2022