Displacement r is r r and time interval is t = (3.00 1.00)s = 2.00s

When t=1.00s, the place is

r = ( 9.60(1.00)i 8.85j 1.00(1.00)k ) m

. . = ( 9.60i 8.85j 1.00k ) m

When t=3.00s, the place is

r = ( 9.60(3.00)i 8.85j 1.00(3.00)k ) m

. . = ( 28.8i 8.85j 9.00k ) m

When t=1.00s, the place is

r = ( 9.60(1.00)i 8.85j 1.00(1.00)k ) m

. . = ( 9.60i 8.85j 1.00k ) m

Common veocity v = r /t

= [ ( (28.8-9.60)i (8.85-8.85)j (9.00-(-1.00)k ) ] / 2.00 m/s

= [ ( 19.2i 0j 8.00k ) ]/2.00 m/s

= ( 9.6i 0j 4.00k ) m/s

r = ( 9.60ti^ 8.85j^ 1.00t2ok^)m,

So,

For, t= 1sec, r(1) = ( 9.60i^ 8.85j^ 1.00t2ok^)m, [1]

and

For, t = 3 sec, r(3) = ( 9.60*3i^ 8.85j^ 1.00t2ok^)m = ( 28.80i^ 8.85j^ 1.00t2ok^)m, . [2]

So,

Common velocity = [r(3) r(10] / (3 1) =( 14.40i^ 0.0j^ 0.02ok^)m/sec. <-/

This post is last updated on hrtanswers.com at Date : 1st of September – 2022