What is the final temperature of the gas [Solved]

Note that answer does not depend on the process,
(which cannot be isobaric btw, because in that case
expansion is incompatible with decrease of temperature)

DU=DQ-DW=1200-2120=920J

DU=DQ-DW=1200-2120=920J

Change in T = (energy) / (moles) / (heat capacity)
=-920J / 5 mol / 20.7863 J/mol-K =
= -8.852K

Change in T = (energy) / (moles) / (heat capacity)
=-920J / 5 mol / 20.7863 J/mol-K =
= -8.852K

Change of internal energy
E = Q A = 1200 2120 = -920J

Internal energy of n moles of monatomic gas:
E = nCvT = 3/2 nRT
E = 3/2 nRT

Answer:
T = 2/3 (Q-A)/nR = -14.74 C
T = To T = 113.25 C

Note that answer does not depend on the process,
(which cannot be isobaric btw, because in that case
expansion is incompatible with decrease of temperature)

Answer:
T = 2/3 (Q-A)/nR = -14.74 C
T = To T = 113.25 C

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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