What was the average force exerted by the ball on the glove [Solved]

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vf^2=vi^2 2ad
0=55^2 2(.25)a
0=3025 .5a
a=-6050m/s/s
F=ma
F=(.145)(-6050)
F=-877.25 N

vf^2=vi^2 2ad
0=55^2 2(.25)a
0=3025 .5a
a=-6050m/s/s
F=ma
F=(.145)(-6050)
F=-877.25 N

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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