Reply 7

Reply 7

Y=3 6x is the one one that does not mach as a result of the graph and the work drawback is y=2 6x

y = 3 6x Step-by-step rationalization: Allow us to substitute x = 0, then we get

y = 3

This isnt the case because the graph clearly reveals that when x = 3, then y = 2

y = 2 6x

when x = 0 then y = 2 which legitimate from the graph

Now put x values from the desk into the equation

y = 2 6-1

y = -4

x = 0 already solved

x = 2

y = 2 62

y = 14

All of the values match within the equation. So, the underside two choices are legitimate.

Therefore, the primary equation is just not legitimate.

Reply 7

Y=3 6x is the one one that does not mach as a result of the graph and the work drawback is y=2 6x

Hope i helpedCheers,Belive1234

For, x = -3; y = 3(-3) 5 = -9 5 = -4For x = 1; y = 3(1) 5 = 3 5 = 8For x = 4; y = 3(4) 5 = 12 5 = 17 Thus the desk representing the operate is the desk with: -3, 1 and 4 as x-values and -4, 8, 17 as y-values. For x = 0; y = 3(0) 5 = 0 5 = 5For y = 0; 0 = 3x 5; 3x = -5 and x = -5/3 Thus the graph of the operate is a straight line passing by factors (0, 5) and (-5/3, 0). For instance the fuction as a phrase assertion we are saying that y is 5 greater than 3 times x From the given descriptions, the graph doesnt signify the graph of y = 3x 5. Due to this fact, the one that doesnt describe the identical state of affairs is the graph.

Reply 7

Y=3 6x is the one one that does not mach as a result of the graph and the work drawback is y=2 6x

This post is last updated on hrtanswers.com at Date : 1st of September – 2022