A ski starts from rest and slides down a 28 incline 130 m long. Use energy methods. [Solved]

The skiers kinetic energy will be 0 when:
0.09mgs = mv^2 / 2
s = v^2 / ( 2 * 0.09 * 9.81 )
= 563.3 m.

The skiers potential energy initially is:
mg 130 sin(28)

The loss through friction is:
0.09mg 130 cos(28)

(a)
Equating potential energy less friction loss to kinetic energy at the bottom:
130m * 9.81(sin(28) 0.09 cos(28)) = mv^2 / 2
v = sqrt[ 2 * 130 * 9.81(sin(28) 0.09cos(28)) ]
= 31.5 m/s.

(b)
The friction force on the level is 0.09mg.

The skiers kinetic energy will be 0 when:
0.09mgs = mv^2 / 2
s = v^2 / ( 2 * 0.09 * 9.81 )
= 563.3 m.

Ski Slides

i think you will fall down

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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