A turntable that is initially at rest is set in motion with a constant angular acceleration. [Solved]

Note: The proper spelling for the name of the Greek letter is pi.

I assume the constant angular acceleration is equal to a (in rad/s^2).
After a time t (in seconds) the angular velocity is w = a t (in rad/s).

After one revolution, the angle traveled is 2 pi = (1/2) a t^2 = w^2 / 2a
Therefore, the angular velocity is w = 2 sqrt (pi*a) [Answer = d]

Note: The proper spelling for the name of the Greek letter is pi.

Source(s): http://www.numericana.com/answer/physics.htm
http://www.numericana.com/answer/constants.htm#pi

permit w be the angular speed. at t=0 w=0 and theta=0 (preliminary angular place) Now use the eqn w^2-w0^2=2.alpha.theta theta=perspective travelled. word:This eqn is such as linear speed one v^2-u^2=2 a s. Now after 2 pi turn theta=2.pi w^2=2.2pi.alpha =4pi.alpha so the angular vel w=2sqrt(pi.alpha) w could properly be clockwise or anticlockwise IVAN

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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