An alkene reacts with a strong protic acid to form a carbocation. In Part 1 draw the curved arrow notation for the reaction between [Solved]

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See clarification and picture connected Rationalization: Now, we now have chosen the alkene 1-propene in our instance. Within the first response of 1-propene with HBr, the response proceeds by ionic mechanism resulting in the formation of 2-bromo propane. Within the second response of 1-propene with the bromine molecule, step one is the formation of the brominium cation which is a cyclic intermidiate adopted by the addition of Br^- yielding the 1,2- dibromopropane product

the best reply is c i simply did the query.

the best reply is c i simply did the query.

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