An electron with an initial speed of 5.0010^5 m/s is brought to rest by an electric field [Solved]

v=u/q v=( 1.14 10^ 19)/( 1.6 10^ -19) = 0.711 volt

1)First, we figure out the variation of electrons kinetic energy:

k = k2 k1 = 0 k1 0 k 0

u = k 0 u 0

3)K1= k=0.711 ev

v=u/q v=( 1.14 10^ 19)/( 1.6 10^ -19) = 0.711 volt

k = 0.711 ev

Get Answer for  The concept of market efficiency underpins almost all financial theory and decision models. When financial markets are efficient, [Solved]