so we need another 23 ml of KOH solution reach the 2nd equiv pt.

Balanced equation for first equiv point

Source(s): chemist

so we need another 23 ml of KOH solution reach the 2nd equiv pt.

Source(s): chemist

Source(s): chemist

volume KOH solution = .0023 moles KOH over .1018 Molar KOH = .023 Liters or 23 ml

volume KOH solution = .0023 moles KOH over .1018 Molar KOH = .023 Liters or 23 ml

Source(s): chemist

Moles H2SO3 = .117 Molar times .020 Liters = .0023 moles

HSO3- plus KOH = K plus SO3= plus H20

2 After the first equiv pt we still had .0023 moles of HS03- remaining which would require another .0023 moles of KOH to reach the 2nd equiv pt.

This post is last updated on hrtanswers.com at Date : 1st of September – 2022