For this reaction:

Gr = Gr RTln[ p(PCl)p(Cl) / p(PCl) ]

= 39000J/mol 8.314472J/molK 298.15K ln[ 0.27 0.40 / 0.0029 ]

= 47967J/mol

48kJ/mol

a)

Gr = Gf_products Gf_reactants

That means for this reaction

Gr = Gf(PCl) Gf(Cl) Gr(PCl)

= -286kJ/mol 0kJ/mol (-325kJ/mol)

= 39kJ/mol

Standard gibbs enthalpy of reaction and equilibrium constant are related as:

Gr = RTlnKp

Hence,

Kp = e^[ Gr / (RT) ]

= e^[ 39000J/mol / (8.314472 298.15K) ]

= 1.4710

b)

In general

Gr = Gr RTlnQr

(Qr is the reaction quotient)

For this reaction:

Gr = Gr RTln[ p(PCl)p(Cl) / p(PCl) ]

= 39000J/mol 8.314472J/molK 298.15K ln[ 0.27 0.40 / 0.0029 ]

= 47967J/mol

48kJ/mol

b)

In general

Gr = Gr RTlnQr

(Qr is the reaction quotient)

This post is last updated on hrtanswers.com at Date : 1st of September – 2022