Calculate delta G(degrees) and Kp for the following equilibrium reaction at 25C [Solved]

For this reaction:
Gr = Gr RTln[ p(PCl)p(Cl) / p(PCl) ]
= 39000J/mol 8.314472J/molK 298.15K ln[ 0.27 0.40 / 0.0029 ]
= 47967J/mol
48kJ/mol

a)
Gr = Gf_products Gf_reactants

That means for this reaction
Gr = Gf(PCl) Gf(Cl) Gr(PCl)
= -286kJ/mol 0kJ/mol (-325kJ/mol)
= 39kJ/mol

Standard gibbs enthalpy of reaction and equilibrium constant are related as:
Gr = RTlnKp

Hence,
Kp = e^[ Gr / (RT) ]
= e^[ 39000J/mol / (8.314472 298.15K) ]
= 1.4710

b)
In general
Gr = Gr RTlnQr
(Qr is the reaction quotient)

For this reaction:
Gr = Gr RTln[ p(PCl)p(Cl) / p(PCl) ]
= 39000J/mol 8.314472J/molK 298.15K ln[ 0.27 0.40 / 0.0029 ]
= 47967J/mol
48kJ/mol

b)
In general
Gr = Gr RTlnQr
(Qr is the reaction quotient)

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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