Calculate the concentration of all species in a 0.225M C6H5NH3Cl solution [Solved]

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i need to find : [C6H5NH3 ], [Cl-], [C6H5NH2], [H3O ], [OH-]. i know how to find find [H3O ] and [OH-] but not for the other three. i really appreciate your help!!

Kb of aniline is 4.0 x 10^-10
C6H5NH3 H2O <-----> C6H5NH2 H3O
Ka = Kw/Kb =2.5 x 10^-5 = x^2 / 0.225-x
x = [C6H5NH2] = [H3O ] = 0.00237 M
[C6H5NH3 ] = 0.225 0.00237 =0.223 M
[OH-] = 10^-14 / 0.00237 =4.22 x 10^-12 M
[Cl-]= 0.225 M

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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