GO VOLS!

Use the equation: E^0 = 0.059/n x log K

a) Cu ====> Cu^2 2e- -0.337

Ag e- === Ag 0.799 not 0.0799

-0.337 0.799 = 0.462

To write the balanced equation, the silver half reaction is multiplied by 2 so that the number of electrons

gained equals the number lost. Thus, n in the total number of electrons transferred, which is 2

0.462 = 0.059/2 x log K ; log K = 15.6 K = 10^15.6 = 3.98 x 10^15

b) n = 3 E^o = 1.61 0.32

c) n 4

Fern gave a good explanation. Your plugged in values should be:

A: 4.2 * 10^15

B: 2.8 * 10^65

C: 7.6 * 10^39

0.462 = 0.059/2 x log K ; log K = 15.6 K = 10^15.6 = 3.98 x 10^15

b) n = 3 E^o = 1.61 0.32

c) n 4

Source(s): Mastering Chem Answers Youre welcome.

This post is last updated on hrtanswers.com at Date : 1st of September – 2022