Can someone help me out with this Physics question [Solved]

A photoresistor, whose resistance decreases with light intensity, is connected in the circuit of the figure. On a sunny day, the photoresistor has a resistance of 0.70 k . On a cloudy day, the resistance rises to 4.6 k . At night, the resistance is 27 k . (Figure 1)

The resistance the 9v battery sees = Rp 1000 where Rp is the resistance of the photo resistor.
Therefore the current out of the battery = 9/(Rp 1000) Amps and the voltmeter
reading = 9/(Rp 1000) * 1000 = 9000/(Rp 1000) = Vm
1) What does the voltmeter read on a sunny day
9000/(700 1000) = 5.3 volts <----- 1) 2) What does the voltmeter read on a cloudy day 9000/(4600 1000) = 1.6 volts <----- 2) 3) What does the voltmeter read at night 9000/(27,000 1000) = 0.32 volts <----- 3) Does the voltmeter reading increase or decrease as the light intensity increases a. The voltmeter reading increases because the current through the resistor increases. You can see that above: 5.294 > 1.607 > 0.3214

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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