Determine the mass of oxygen in a 7.2-g sample of Al2(SO4)3. [Solved]

0.0210 moles Al2(SO4)3 X (12 mol O / 1 mol Al2(SO4)3) X 16.0 g/mol O = 4.0 g O

0.0210 moles Al2(SO4)3 X (12 mol O / 1 mol Al2(SO4)3) X 16.0 g/mol O = 4.0 g O

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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