# Given: Circle O with diameter LN and inscribed angle LMN Prove: is a right angle. What is the missing reason in step 5 [Solved] As a result of OL = OM = ON = the radius, subsequently every of OLM andONM is an isosceles triangle.OLM has two equal angles denoted by a, and ONM has two equal angles denoted by b. The central angles x and y add as much as 180 on a straight line, sox y = 180 (1) As a result of angles in a triangle sum to 180, thereforex 2a = 180 (2)y 2b = 180 (3) Add (2) and (3) to obtainx y 2(a b) = 360 From (1), obtain180 2(a b) = 3602(a b) = 180a b = 90 As a result of (a b) =LMN, it proves thatLMN = 90

step 5= inscribed angle theorem Rationalization:

step 5= inscribed angle theorem Rationalization:

As a result of OL = OM = ON = the radius, subsequently every of OLM andONM is an isosceles triangle.OLM has two equal angles denoted by a, and ONM has two equal angles denoted by b. The central angles x and y add as much as 180 on a straight line, sox y = 180 (1) As a result of angles in a triangle sum to 180, thereforex 2a = 180 (2)y 2b = 180 (3) Add (2) and (3) to obtainx y 2(a b) = 360 From (1), obtain180 2(a b) = 3602(a b) = 180a b = 90 As a result of (a b) =LMN, it proves thatLMN = 90

step 5= inscribed angle theorem Rationalization:

The reply isB) Inscribed Angle Theorem